a vector has a magnitude of 50 in the 35º direction. what are the horizontal and vertical components of this vector?

Answer: Horizontal component: 40.95 Vertical component: 28.67Step-by-step explanation: To find the horizontal and the vertical component of this vector, you need: The formula for calculate the horizontal component: [tex]a_x=|a|cos\alpha[/tex] Where [tex]|a|[/tex] is the magnitude The formula for calculate the vertical component: [tex]a_y=|a|sin\alpha[/tex] Where [tex]|a|[/tex] is the magnitude Given the angle 35 degrees and the magnitude,you can substitute values into the formulas. Therefore, you get  that the horizontal component and the vertical component of this vector are: [tex]a_x=50cos(35\°)=40.95[/tex] [tex]a_y=50sin(35\°)=28.67[/tex]